Chapter 30, Problem 018 In the figure below, two straight conducting rails form

Question

Chapter 30, Problem 018 In the figure below, two straight conducting rails form a right angle. A conducting bar in contact with the rails starts at the vertex at time t0 and moves with a constant velocity of 7.72 m/s along them. A magnetic field with B 0.396 T is directed out of the page. Calculate (a) the flux through the triangle formed by the rails and bar at t- 4.19 s and (b) the emf around the triangle at that time. (c) If the emf is = atn, where a and n are constants, what is the value of n? UB- (a) Number (b) Number (c) Number Units Units Units

Explanation / Answer

flux = B*A

A = area of triangle = (1/2)* base*height

base = height = a = v*cos45

flux = B*(1/2)*a^2

flux = B*(1/2)*(v*cos45*t)^2

flux = (1/2)*B*v^2*(cos45)^2*t^2

flux = (1/2)*0.396*7.72^2*(cos45)^2*4.19^2

flux = 5.9*t^2

flux = 103.6 wb

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part (b)

emf = rate of change in flux

emf = 5.9*2*t

emf = 5.9*2*4.19

emf = 49.442 V

=================

part(c)

a = 5.9

n = 1

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