Chapter 30, Problem 015 A square wire loop with 2.2 m sides is perpendicular to

Question

Chapter 30, Problem 015 A square wire loop with 2.2 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field as shown in the figure. The loop contains an ideal battery with emf 8- 15 V. If the magnitude of the field varies with time according to B 0.045-0.85 t, with 8 in teslas and t in seconds, what are (a) the net emf in the circuit and (b) the direction of the (net) current around the loop? es Min bat tudy the tolerance is +/-596 Question Attempts: O of S used SAVE FOR LATER SUBMIT ANSWER

Explanation / Answer

side of the loop, a = 2.2 m

E = 15 V

B = 0.45 - 0.85t

a. Net emf in the battery = E + V

where V is induced emf

now form the circuit

V = -d(phi)/dt

phi = B*a^2/2 = (0.45 - 0.85t)*2.42

hence V = 2.057 V

hence

net EMF = 17.057 V

b. direction of net current around the loop = anticlockwise from +ve end of the battery to the -ve end

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