4. -4 points O5ColPhys2016 2.3.P011 My Notes Ask Your A student drove to the uni

Question

4. -4 points O5ColPhys2016 2.3.P011 My Notes Ask Your A student drove to the university from her home and noted that the odometer on her car increased by 12.0 km. The trip took 19.0 min (a) What was her average speed in km/h? km/h (b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her average velocity in km/h? km/h (e) If she returned home by the same path 7 h 30 min after she left, what were her average speed and velocity in km/h for the entire trip? average speed average velocity km/h km/h Additional Materials Reading 5. +-1 points OSColPhys2016 2.3.P012. My Notes Ask Your The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 0.9 m long, and the nerve impulse speed is 25 m/s, how long (in s) does it take for the nerve signal to travel this distance? Additional Materials Reading

Explanation / Answer

4)

Distance: 12 km

time: 19 min = 19/60 hours = 0.31666 hours

speed = distance / time

speed = 12/0.31666

speed = 37.895 km/h

b)

velocity = displacement/time

v = x/t

displacement is 10.3 km (in the direction of 25 S of E)

t = 0.31666 hours

v = 10.3/0.31666

v = 32.527 km/h

c)

1)

d = 12 x 2 = 24 km

t = 7.5 h

v = d/t

v = 24/7.5

v = 3.20 km/h

2)

v = x / t = xf - xi = 0 - 0 = 0 km (she started and ended at the same position)

v = 0/7.5 = 0 km

5)

time = distance / time

t = d/v

t = 0.9 m / 25 m/s

t = 0.036 s

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