(a) What is the intensity of the light reaching the screen now? The angle of the

Question

(a) What is the intensity of the light reaching the screen now?

The angle of the transmission axis of the first polarizer is now set to +36.0°, and kept there. A second polarizer is placed over the first one, so the light passes through both polarizers before reaching the screen. The angle of the transmission axis of the second polarizer is initially +17.0°.

(c) Calculate the intensity of the light reaching the screen now.

(d) When the second polarizer is rotated clockwise a little, so the angle its transmission axis makes with our reference line is more than +17.0°, the light reaching the screen does which of the following?

gets brighter, with no change in the angle at which it is polarized

gets brighter, and it experiences a change in the angle at which it is polarized    

gets dimmer, with no change in the angle at which it is polarized

gets dimmer, and it experiences a change in the angle at which it is polarized

stays the same intensity, with no change in the angle at which it is polarized

stays the same intensity, but it experiences a change in the angle at which it is polarized

(e) At what angle should the transmission axis of the second polarizer be set to, to maximize the intensity of the light reaching the screen? Your answer should be in the range 89° to +90°.

(f) At what angle should the transmission axis of the second polarizer be set to, to minimize the intensity of the light reaching the screen? Your answer should be in the range 89° to +90°.

An overhead projector is turned on so its light shines on the screen at the front of the classroom. The light from the projector is unpolarized, and the intensity of the light reaching the screen is 520 W/ A single polarizer is then placed on the projector, so the light passes through the polarizer before reaching the screen. The transmission axis of the polarizer is aligned at a +36.0° angle (see the picture to see exactly what direction this is). 0° -30 -60° +60° +90

Explanation / Answer

(A) I = I0/2 = 260 W/m^2

(C) I = (260) (cos(36-17))^2

I = 232.4 W/m^2

(d) theta - decrease - > cos(theta) -> increase

intensity inccreas

Ans: gets brighter and eperience a change in the agle at which its is polarized

(e) theta = 0 => cos0 = 1

hence angle = 36 deg

(f) theta = 90 = > cos90 = 0

angle = 36 - 90 = - 54 deg

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