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(890) Problem 9: Consider a bar, of length 5.5 m, shown in the figure, being act

ID: 1776415 • Letter: #

Question

(890) Problem 9: Consider a bar, of length 5.5 m, shown in the figure, being acted on by three forces. The magnitudes of the first two forces are 26 N and 31 N, and the first force is acting on the end of the bar at an angle of 31° as shown. F3 Fi 33% Part (a) what is the torque, in newton-meters, due to F1 on this bar relative to the left end? Use a coordinate system with positive directed out of the screen. Grade Summary Potential Submissions Attempts remaining:- 096 100% cotan asinacos0 atan0 acotan0 sinh0 cosh0 tanh0cotanh0 O DegreesRadians 6per attempt etailed view END Submit Hint I give up! Hints: 5% deduction per hint. Hints remaining: 2 Feedback: 2% deduction per feedback. - 33% Part (b) What is the torque in newton-meters, due to F2 on this bar relative to the left end if this force is acting at the midpoint of the bar? Use a coordinate system with positive directed out of the screen. 33% Part (c) what is the magnitude of the force F, in newtons, ifthe force is a distance 0.55 m from the left end and the bar is not rotating?

Explanation / Answer

(a) torque = r x F = r F sin(theta)

t1 = L F1 sin(phi) = 5.5 x 26 x sin31

t1 = 73.65 N m

(b) t2 = (5.5/2)(31) = 85.25 N m


(c) for eq., net torque = 0

73.65 + 85.25 - (0.55 F3) = 0

F3 = 289 N