(8%) Problem 8: An arrow is shot from a height of 1.55 m toward a cliff of heigh

Question

(8%) Problem 8: An arrow is shot from a height of 1.55 m toward a cliff of height H It is shot with a velocity of 25 m/s at an angle of 60° above the horizontal. It lands on the top edge of the cliff3.86 s later. 33% Part (a) What is the height Hof the cliff in m? Grade S tano l (III 7 8 9 submiss cotano asino acoso Attempt atanO acotan0 sinh0 Degrees O Radians I give up! Submit Feedback deduction per feedback. Hints i deduction per hint. Hints remaining i A 33% Part b) What is the maximum height reached by the arrow along its trajectory in meters A 33% Part (c) What is the arrow's speed just before hitting the cliff in m s?

Explanation / Answer

H - 1.55 = uyt - (1/2)gt2

=> H - 1.55 = 25sin60(3.86) - (1/2)(9.8)(3.86)2

=> H = 12.11m.

b] At the maximum height, vy = 0 m/s

so, 02 = uy2 - 2g[h - 1.55]

=> h = 25.466 m.

c] When the arrow hits the cliff, vy = uy - gt = 25sin60 - 9.8(3.86) = - 16.177 m/s

and vx = ux = 25cos60 = 12.5 m/s

therefore, the speed will be: |v| = [(12.5)2 + (- 16.177)2]1/2 = 20.44 m/s.

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