(8%) Problem 10: A car is traveling at constant speed of v Randomized Variables

Question

(8%) Problem 10: A car is traveling at constant speed of v Randomized Variables v27.3 m/s 27.3 m/s. Its tires have a diameter of d = 0.93 m d 0.93 m 50% Part (a) Consider a point on the outer edge of the tire. What is the centripetal acceleration, ac at this point in m s2? ae1602.774 ac 1603 Correct! ( 50% Part (b) If the car was traveling twice as fast, what would be the numerical value of the ratio of the new centripetal acceleration, an, to the old centripetal acceleration? Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: 5 (10% per attempt) detailed view cosO cotan0 asin) atan)acotan) acos0 sinh0 cosh0 n cotanh0 1 23 0 Degrees O Radians 0 Submit Hint Hints: 5% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback

Explanation / Answer

It's quite straightforward

centripetal acceleration is directly proportional to square of velocity

so, doubling the velocity will make the accn 4 times

Answer is 4

upvote if it helps

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