(8%) Problem 10: A conducting rod of length L = 0.025 m is lying on a rectangula

Question

(8%) Problem 10: A conducting rod of length L = 0.025 m is lying on a rectangular wire as shown in the figure. A constant magnetic field with magnitude B = 0.35 T pointing into the paper is in the region. The rod is pulled to the right by an external force, and moves with constant speed v =0.11 m/s. The resistance in the wire is R = 180 Randomized Variables L = 0025 m B = 0.35 T v=0.11 m/s R=180 ©theexpertta.com là 14% Part (a) Express the magnitude of the magnetic flux going through the loop, , in terms of B, a and L 14% Part (b) Express the change in the magnetic flux, , in terms of B, L, v and t 14% Part (c) Express the magnitude of the average emf induced in the loop, e, in terms of B, L, v 14% Part (d) Calculate the emf, in volts 14% Part (e) Express the current induced in the loop, I, in terms of and R 14% Part (f) Calculate the value of 1, in amperes 14% Part (g) What is the direction of the current? Grade Summary Deductions Potential Clockwise. Counterclockwise 0% 100% Submit Hint I give up! Submissions Attempts remaining:1 (100% per attempt) detailed view Hints: 1 % deduction per hint. Hin ts remaining: Feedback: 1% deduction per feedback.

Explanation / Answer

part (a)

magnetic flux phi = B*A = B*a*L

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part b)

distance moved in time dT, da = v*dT

change in flux = dphi = B*L*da = B*L*v*dT

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part c

average emf = rate of change in flux

emf = dphi/dT = B*L*v

======================

part (d)

emf = 0.35*0.025*0.11 = 0.0009625 V

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part(e)

current i = emf/Resistance = e/R

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part(f)

current I = 0.0009625/180 = 5.35*10^-6 A

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part (g)

counterclockwise

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