In Part 1, calculate the percentage of momentum and kinetic energy “lost during
ID: 1776584 • Letter: I
Question
In Part 1, calculate the percentage of momentum and kinetic energy “lost during the collision.What are the possible sources that causes the loss? Where did the lost energy go?
Trial
M1[kg]
M2[kg]
V1[m/s]
V1'[m/s]
V2[m/s]
V2'[m/s]
1
0.1779kg
0.1793kg
0.33 m/s
0 m/s
0 m/s
0.3188 m/s
2
0.1779kg
0.2793kg
0.5975 m/s
0.1090 m/s
0 m/s
0.298 m/s
3
0.2779kg
0.1793kg
0.4598m/s
0m/s
0 m/s
0.5366 m/s
Trial
M1[kg]
M2[kg]
V1[m/s]
V1'[m/s]
V2[m/s]
V2'[m/s]
1
0.1779kg
0.1793kg
0.33 m/s
0 m/s
0 m/s
0.3188 m/s
2
0.1779kg
0.2793kg
0.5975 m/s
0.1090 m/s
0 m/s
0.298 m/s
3
0.2779kg
0.1793kg
0.4598m/s
0m/s
0 m/s
0.5366 m/s
Explanation / Answer
I am doing calculations for Trial 1.
initial momentum =( 0.1779) (0.33) +0.1793 (0) =0.058707 kg m/s
final momentum = (0,1779) (0) +(0.1793)(0.3188) =0.05716084
% loss in momentum= ( 0.058707- 0.05716084) / 0.058707 x 100= 2.633 % apprx
Initial KE = 1/2 ( 0.1779 ) (0.33^2) =0.009686655
Final KE = 1/2 (0,1793) (0,3188^2) =0.009111437896
% loss in KE =( 0.009686655- 0.009111437896)/ 0.009686655) x 100= 5.94 %
sources= friction, sound produced during collision, heat produced in collision.
KE gets converted to other forms of energies( like heat and sound)
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