In Part 2 of Lab #12 you will also determine AGdegree for the solid dissolving i
ID: 921945 • Letter: I
Question
In Part 2 of Lab #12 you will also determine AGdegree for the solid dissolving in water. Suppose you use the same solid as in Question #3 (that is, the molar mass is 86.9 g/mol) and obtain the following data: Determine the concentration of the solid. Determine Delta G degree if we assume K = [solid] in the saturated solution. Determine the value of the equilibrium constant, K, if we take into account the volume of water added to the saturated solution. Determine Delta G degree if we take into account the volume of water added to the saturated solution.Explanation / Answer
1)
here I am assuming that water is not added to solution
number of moles of solid = mass/ molar mass
= 2.957/86.9
= 0.034 mol
volume of solution = 5.47 mL = 0.00547 L
concentration of solid = number of moles/ volume
= 0.034 mol / 0.00547
= 6.22 M
2)
K = [Solid]
so,
K = 6.22
T = 25.9 oC = (25.9 + 273) K= 298.9 K
use:
delta G= -R*T*ln K
= -8.314 * 298.9* ln 6.22
= -4542 J/mol
= -4.542 KJ/mol
3)
after water is added
number of moles of solid = mass/ molar mass
= 2.957/86.9
= 0.034 mol
concentration of solid = number of moles/ volume
= 0.034 mol / (0.00547+0.00311)
= 3.963 M
K = [Solid]
so,
K = 3.963
4)
T = 25.9 oC = (25.9 + 273) K= 298.9 K
use:
delta G= -R*T*ln K
= -8.314 * 298.9* ln 3.963
= - 3421.8 J/mol
= - 3.422 KJ/mol
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