how large a force is necessary to stretch a 2.0mm diameter steel wire (Y= 2.0 x

Question

how large a force is necessary to stretch a 2.0mm diameter steel wire (Y= 2.0 x 10^11 how large a force is necessary to stretch a 2.0mm diameter steel wire (Y= 2.0 x 10^11 how large a force is necessary to stretch a 2.0mm diameter steel wire (Y= 2.0 x 10^11 how large a force is necessary to stretch a 2.0mm diameter steel wire (Y= 2.0 x 10^11 16. A 20.0 kg child is riding a playground merry-go-round that is rotating at 4.2 rad/s. The centripetal force (in N) she must exert to stay on if she is 2.50 m from its center is (a) 882 N (b) 210 N (c) 84 N (d) 100 N

Explanation / Answer

We know that,

Fc = ma

= mw^2*r

where. F is centripetal force

= 20*4.2^2*2.5

= 882 N Answer

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