how it this done? 4. (8 pts) In fruit flies, the yellow gene controls pigmentati

Question

how it this done?

4. (8 pts) In fruit flies, the yellow gene controls pigmentation. The yellow allele (v) gives flies a yellow colored body and is recessive to the wildtype allele (v') which yields a brown body color. Another gene, crossveinless, determines the wing vein pattern. The crossveinless allele (cv) is recessive to the wildtype allele (cv'). A heterozygous female with mutant alleles in the repulsion (transconfiguration, is test crossed to a male homozygous recessive for both genes. The two genes are approximately 12 m.u. apart. Fill in the table below with the predicted phenotypic frequency for the progeny from this cross. Phenotype % of Progeny wildtype body color, wildtype wings (y cv') NX yellow body, crossveinless wings (y cv) lw wildtype body color, crossveinless wings (y' cv) NR yellow body, widltype wings (ly cv') 44/

Explanation / Answer

The distance between both the genes = 12 mu

i.e. Recombination frequency = 12%

It means that the given two genes can independently segregate only 12% of the times.

The remaining 88% of the time they are assorted together.

So, the parental combinations = 88%

Recombinants = 12%

There are two parental combinations. Both will have an equal frequency.

WT body color and WT wings = 44%

Mutant body color and mutant wings = 44%

There are two recombinant progeny. Both will have an equal frequency.

WT body color and mutant wings = 6%

Mutant body color and WT wings = 6%

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