Extra-problem not in the book A woman who weighs 5.00 x 102 Nis leaning against
ID: 1777046 • Letter: E
Question
Extra-problem not in the book A woman who weighs 5.00 x 102 Nis leaning against a smooth vertical wall, as the drawing shows. Find (a) the force FN(directed perpendicular to the wall) exerted on her shoulders by the wall and the (b) horizontal (F2) and (c) vertical components of the force (F1) exerted on her shoes by the ground F1 and F2 are the two additional forces acting at the feet of the woman 1.10 m F1 F2 Tip: Draw the free-body diagram with the three forces and get the Fnet 0 along x and y, then get the net torque nets 0 with the pivot at the feet. You will get three equations.Explanation / Answer
Given,
W = 5 x 10^2 N ;
a)from figure, the net torque from the point of contact
500 x 1.1 x sin30 = Fn cos30 x 1.5
Hence, Fn = 212 N
b)Fh - Fn = 0
Fh = Fn = 212 N
Hence, Fh = 212 N
c)Fv = W = 500 N
Hence, Fv = 500 N
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