A plastic block that has a length of 0.4 m, a width of 0.25 m, and a height of 0

Question

A plastic block that has a length of 0.4 m, a width of 0.25 m, and a height of 0.27 m, and has a density of 690 kg/m3 floats in both water and oil (a) If the plastic block is floating at the surface of a tank of water (which has a density of 1000 kg/m3), what is the distance from the top of the block to the surface of the water? (b)If the plastic block is floating at the surface of a tank of oil (which has a density of 900 kg/m3), what is the distance from the top of the block to the surface of the oil?

Explanation / Answer

(A) Fnet = Fb - m g = 0

Fb = buoyant force = Weight of displaced water

Fb = V_submerged x rho x g

Fnet = (0.4 x 0.25 x h)(1000)g - (0.4 x 0.25 x 00.27)(690)g = 0

h = 0.27 x 690/1000 = 0.19 m

d = 0.27 - h = 0.08 m

(b) Fnet = (0.4 x 0.25 x h)(000)g - (0.4 x 0.25 x 00.27)(690)g = 0

h = 0.27 x 690/900 = 0.21m

d = 0.27 - h = 0.06 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.