11 please B) The force of static friction on ml is less than TI C) T3 is equal i

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11 please

B) The force of static friction on ml is less than TI C) T3 is equal in magnitude to T2 D) If the table was completely frictionless, the system as shown could not be in cquilibrum E) The net force on the knot is upwards. Answe Submit All Answers Last Answer: FITTF Not yet correct, tries 4/6 10.[lpt] In the previous problem, block mi weighs 756 N. The coefficient of static friction between the block and the table is 0.27 and the angle theta is 29.2°. Find the maximum weight of block m for which block mi will remain at rest. Correct, computer gets: 1.14E+02 N 11. [Ipt] A mass M is initially at rest on a horizontal surface, mu, -0.30 and muk-0.20. A horizontal string then pulls M with a tension T. Forces below are magni or False (if only B is True, enter FTFFFF) tudes. State whether the below answers are True A) The NET force on M (if M does not move) is muyN B) N equals Mg C) T equals mu, N if M remains at rest D) M will accelerate if T exceeds mus N E) M will accelerate if T exceeds muN F) If M does not accelerate, then T is less than or equal to musN Answer: Incorrect, tries 4/6. Submit All Answers Last Answer: TFTFFT oto problem [1]213 I4115116117)[8]9110][11] Status: Y YN N Y YYNY N O Type here to search

Explanation / Answer

A) if object is not moving then net force on that will be zero. So FALSE

B) By vertical equilibrium N = mg. So TRUE

C) The block will be at rest even if T < musN. So FALSE

D) Limiting friction force is musN so if tension exceeds to this value then block will accelerate. So TRUE

E) Block will not start moving untill the value of T exceeds musN. So FALSE.

F) TRUE

SO FTFTFT

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