(25%) Problem 2: An electron (m = 9.109 × 1031 kg) is in the presence of a const
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(25%) Problem 2: An electron (m = 9.109 × 1031 kg) is in the presence of a constant electric field E. The electron has a charge of e = 1.602 × 10-19 C and it accelerates at a rate of a = 1900 m/s2. 33% Part (a) Write an expression for the magnitude of the electric field 33% Part (b) What is the field, in units of N/C? 33% Part (c) Assuming the electron begins at rest, what is its velocity after 0.55 s? Give your answer in meters per second Grade Summary Deductions Potential 4% 96% Submissions Attempts remaining: 19 (4% per attempt) cos0 cotan)asir atan)acotan cosh)tanh) cotanh) tan() || acos) sinh) detailed view 4% 0 END DegreesRadians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. Submission History Hints Feedbaclk Note: Feedback not accessed Totals 4% 4% Answer 4% 4% 0% 0% v= 10450 0% Totals 0%Explanation / Answer
initial velocity vo = 0
acceleration a = 1900 m/s^2
time interval t = 0.55 s
v = vo + a*t
v = 0 + (1900*0.05)
v = 95 m/s <<<-----ANSWER
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