A block of mass m is released down a ramp from a height h, where it then enters

Question

A block of mass m is released down a ramp from a height h, where it then enters a loop-the-loop of radius R, as shown in the figure. It is observed that the speed of the block at the top of the circle. Your expression should be in terms of the given variables and any other known constants such as acceleration due to gravity, &. The constant vA is typed with the lower case enrolled in this course only. Any distribution of the contents in whole or in parts and in any form, Including posting on the web or in printed version, is a violation of the Copyright laws and the FSU honor codes Send Feedback

Explanation / Answer

here,

the speed at point A is vA

the height is h

the work done by friction , W = initial potential energy - final potential energy - final kinetic energy

W = m * g * ( h - 2R) - 0.5 * m* vA^2

so the work done by frictional force is W = m * g * ( h - 2R) - 0.5 * m* vA^2

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