(13%) Problem 7: Capacitor C1 is initially charged to VI and capacitor C2 is ini
ID: 1780075 • Letter: #
Question
(13%) Problem 7: Capacitor C1 is initially charged to VI and capacitor C2 is initially charged to V2. The capacitors are then connected to each other, positive terminal to positive terminal and negative terminal to negative terminal If C1-26 F with initial voltage of 22 V, and capacitor C2-29 F is charged to 11 V. What is the final voltage, in volts, across C1? Grade Summary Deductions Potential 0% 100% cosO asin) tan() | | ( | acos) Submissions Attempts remaining: S sinO cotan % per attempt) detailed view acotan) sinh() 0 cosh tanh cotanh0 Degrees Radians END BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 2 for a 0% deduction. Hints remaining: 0 Feedback: 0%-deduction per feedback. -Can you calculate to initial charge on each capacitor using the definition of capacitance = q/V? The initial total charge is conserved Since you know VIf = V2f, you can write this equality as Q1fC,- Q2EC2. You know Qif+ Q2f= the initial total charge, which can be used to eliminate Q2fExplanation / Answer
A) here capacitors are in parallel, so equivalent Capacitance = C1+C2 = 26+29 = 55 uF
Total charge = C1V1 + C2V2 = 26*22+29*11 = 891 uC
Final voltage = total charge/capacitance
= 891/55 = 16.2 V answer
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