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session masteringphysics.com Copy of PHYC 150 3/e e session.masteringphysics.com Chapter 09 Problem 9.40 Resources «previous l 170134 next Problem 9.40 Part A A 180 g ball is dropped from a height of 2.1 m and bounces on a hard floor. The force on the baill from the foor is shown in the figure.(Eigure 1) How high does the ball rebound? Express your answer using two significant figures. hs Submit My Answers Give Up Incorrect: Try Again: 7 attempts remaining Continue Figure 1 of 1 F, (N) 1000 2 50 60 0 (ms) .70 .74 on a B

Explanation / Answer

The impulse applied to the ball by the floor is the area under the curve on the plot
the area of a triangle is
A = ½bh
so the impulse is
I = ½(0.004)(1000)
I = 2 Ns

As impulse changes the momentum of an object
the original momentum is mv

y = ½gt²
t = (2y/g)
v = at = gt
v = g(2y/g)
v = 9.81(2(2.1)/9.81)
v = 6.42 m/s

p = mv
p = 0.180(6.42)
p = 1.155Ns

as the original momentum was downward and the impulse was upward,
-1.55 + 2 = 0.45

0.45 = 0.180(v2)
v2 = 2.5 m/s upward

v = gt
2.5 = 9.81t
t = 0.255 s

y = ½gt²
y = ½9.81(0.255)²
y = 0.319 m

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