For the following questians, there is a 269 gram cart maving along a track t a 1

Question

For the following questians, there is a 269 gram cart maving along a track t a 14angle on Earth where the lacal acceleratian due to gravity is 9.91 mis2 For an image please reference page 91 of the lab manual. qurstions, t moving a Question 1 Once the cart has moved 37 cm up the track, it has a speed of 0.32 m/s. What is the total mechanical eneray of the cart? Answer in joules, and to the tourth decimal place. Question 2 5 pts The cart has moved along the track to a point where is has 0.18 joules of total energy and a sperd of 0.11 ms. What is the distance along the trark that the cart has maven? Answer in meters, and to the fourth derimal place. Question 3 5 pts The cart has moved 24 cm along the track to a point where its kinetic energy is 20 mJ(millijoules). What is the total mechanical energy in the cart? Aniswer in jouiles, and to the fourth decimal place. DQuestion 4 5 pts The cart has moved verticallity upward 11 cm to a point where is has 035 joules of total energy. What is the speed of the cart at this location? Answer in meters per second, and to the tourth declimal place.

Explanation / Answer

1. total Me= PE + KE

= m g L sin14 + m v^2 / 2

= (0.269 x 9.81 x 0.37sin14) + (0.269 x 0.32^2 / 2)

= 0.2500 J

2. 0.18 = (0.269 x 9.81 x d sin14) + (0.269 x 0.11^2 / 2)

d = 0.2794 m

3. ME = (0.090 ) + (0.269 x 9.81 x 0.24 sin14)

= 0.2432 J

4. 0.35 = (0.269 x 9.81 x 0.11 ) + (0.269 v^2 / 2)

v = 0.6664 m/s

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