A block of weight a 400 N sits on a frictionless inclined plane, which makers an

Question

A block of weight a 400 N sits on a frictionless inclined plane, which makers anangle :350°with respect to the honzorta as shown in the tp:re Eigure 1) A force of magnitude - 229 N, applied parallel to the incine is ust sufficient to pull the block up the plane at consfant speed Submit My Amswers Give Up Part C What is Wy the work done on the block ty the applied force Fas the blcck moves a distance L- 4 50 m up the incine Express your answer numerically in joules Hints We My Answers Glve Up Part D 1%. wht is WN, the work done on block by he normal force as the block moves adstace450mupte ncined piane, Express your answer numerically in joules. Hints Submit My Answers Give Up

Explanation / Answer

part(A)

from work energy theorem

total work done by all forces = change in KE

Wtot = (1/2)*m*(vf^2 - vi^2)

as the speed is constant vf = vi

Wtot = 0

======================

part (B)

along the incline

component of gravitational force down the incline Fg = m*g*sintheta

Work done by gravity = Fg*L*cos180

Wg = -m*g*sintheta*L

Wg = -40*sin35*4.5

Wg = -103.24 J       <<---------ANSWER

=================================

part(c)

along the incline

component of gravitational force down the incline Fg = m*g*sintheta

Fnet = Fg - F

Fnet = m*a

as speed is constant acceleration a = 0

Fnet = F - m*g*sintheta = 0

F = m*g*sintheta

work done by force F, WF = m*g*sintheta*L = 103.24 J   <<---------ANSWER

=========================================

part (D)

perpendicular to incline

FN - m*g*costheta = 0

FN = m*g*costheta

work done by FN , WN = FN*L*cos90 = 0 <<<<<---------ANSWER

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.