(796) Problem 10: A massless spring of spring constant k = 8501 Nin is connected
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(796) Problem 10: A massless spring of spring constant k = 8501 Nin is connected to a mass m = 377 kg at rest on a horizontal, frictionless surface stored in the spring as a result? maximum kinetic energy for the first time? is equal to 1 BOE = 6.11 78362 GJ Calculate the number, N of springs with spring constant k= 8501 Nm displaced to A-0.97 m you would 20% Part (a) The mass is displaced from equilibrium by.4-0.97 m along the spring's axis. How much potential energy in joules is 20% Part (b) when the mass is released from rest at the displacement. 0.97 m, how much time, in seconds, is required for it to reach its 20% Part (c) The typical amount of energy released when burning one barrel of crude oil is called the barrel of oil equivalent(BOE) and need to store 1 BOE of potential energy. 20% Part (d) Imagine that the springs from part (c) are released from rest simultaneously If the potential energy stored in the springs s fully converted to kinetic energy and thereby "released" when the attached masses pass through equilibrium, what would be the average rate at which the energy is released? That is, what would be the average power, in watts, released by the Nspring system? 20% Part (e) Though not a practical svstem for energv storage, how manv million buildings. B. each using 105 W, could the spring svstem temporarily power Grade Summa Deductions Potential 0% 100% tan() | acosO Submissions Attempts remaining (090 per attempt) detailed view Sin cos cotanasin0 atan cosh0 anh cotanhO acot END Degrees Radians Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining Feedback: 0% deduction per feedback.Explanation / Answer
(A) U = k A^2 /2 = 4000 J
(B) T = 2 pi sqrt(m / k) = 1.32 s
t= T / 4 = 0.33 sec
(d) 6.1178 x 10^9 = N (4000)
N = 1.53 x 10^6 springs
(e) P = (6.1178 x 10^9) / (0.33) = 4.636 x 10^6 W
(f) n = (4.636 x 10^6)/10^5 = 46.4 buildings
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