9. A 20.0-kg disk with a rotational inertia given by MR2/2 is free to rotate on
ID: 1781371 • Letter: 9
Question
9. A 20.0-kg disk with a rotational inertia given by MR2/2 is free to rotate on a fixed horizontal axis suspended from the ceiling. A string is wrapped around the disk and a 3.00-kg mass hangs from the free end. a) What is the weight of the disk? b) What is the acceleration of the mass? c) What is the tension T in the rope? d) If the string does not slip then as the mass falls and the cylinder rotates the suspension holding the cylinder pulls up on the cylinder with a force (Tension) of: Tension mgExplanation / Answer
(a) weight =20*9.8=196 N
(b)let accleration is a
mg-T=ma......(1)
T*R=0.5*M*R*R*a/R...... (2)
We got T=0.5Ma
Putting in (1)we got
a=2.26 m/s*s
(c)T=10a=22.6N
(d)net force=22.6+196=218.6 N
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