FULL sou EN | | PRINTER VERM ON BACK Chapter 11, Problem 003 Accomplished silver
ID: 1781520 • Letter: F
Question
FULL sou EN | | PRINTER VERM ON BACK Chapter 11, Problem 003 Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00 x 10 7 m (about one hundredth of the thickness of a sheet of paper) Find the area of such a sheet that can be formed from 3.20 kg of silver. Number the tolerance is +/-6% Click if you would like to Show Work for this question: Oen Show Work Units SHOW HINT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Pollicy set by your instructor.Explanation / Answer
Total mass of silver = density of silver *volume of the silver sheet
= density of silver * ( thickness of sheet * area of sheet )
Thus, area of sheet = mass of silver / (density of silver * thickness of sheet )
density of silver = 10490 kg/m3
area of sheet = 3.20 / ( 10490 * 3.00 * 10-7 )
= 1016.84 m2
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