hen only a resistor is connected across the terminals of an ac generator (113 V)

Question

hen only a resistor is connected across the terminals of an ac generator (113 V) that has a fixed frequency, there is a current of 0.505 A in the resistor. When only an inductor is connected across the terminals of this same generator, there is a current of 0.408 A in the inductor. When both the resistor and the inductor are connected in series between the terminals of this generator, calculate the following.

(a) the impedance of the series combination

(b) the phase angle between the current and the voltage of the generator °

Explanation / Answer

I1 = E/R

Resistance R = E/I1 = 113/0.505 = 223.8 ohm

when only inductor is connected

I2 = E/(XL) = E/(w*L)

inductive reactance = XL = E/I2 = 113/0.408 = 277 ohms

impedance Z = sqrt(R^2+(XL)^2)

Z = sqrt(223.8^2+277^2) = 356.1 ohm <<<<<--------ANSWER

================

part (b)

phase angle = atan(XL/R)

phase angle = atan(277/223.8) = 51 degrees <<<<<--------ANSWER

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