help... In a bag of M & M plain candies, the colors can be brown, yellow, red, b
ID: 2922777 • Letter: H
Question
help...
Explanation / Answer
1)
a) P(taking out a brown and yellow M&M) = (0.13)(0.14) = 0.0182
b) Proportion of Blue candies = 1 - 0.13 - 0.14 - 0.13 - 0.20 - 0 .16 = 0.24
So, P(selected candy is Blue) = 0.24
c) P(randomly selected M&M is either red, yellow or orange) = 0.13 + 0.14 + 0.20 = 0.47
2)
a) P(randomly selected person is widowed or divorced) = (13.9 + 22.8) / 219.7 = 36.7 / 219.7 = 0.1670
b) P(randomly selected man is widowed or divorced) = (2.6 + 9.7) / 106.2 = 12.3 / 106.2 = 0.1158
3)
a) P(face card is drawn) = 12 / 52 = 0.2308
{There are 12 face cards in a deck of 52 cards}
b) P(a red card or a card showing 5 is drawn) = P(a red card is drawn) + P(a car showing 5 is drawn) - P(a red card and a card showing 5 is drawn)
= (26/52) + (4/52) - (2/52) = 28/52 = 0.5385
c) P(a non-face card or a card showing 7 is drawn) = P(a non-face card is drawn) + P(a car showing 7 is drawn) - P(a non-face card and a card showing 7 is drawn)
= (40/52) + (4/52) - (4/52) = 40/52 = 0.7692
{There are 40 non-face cards in a deck of 52 cards}
d) P(a black face card is drawn) = 6/52 = 0.1154
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