A. Find the change in momentum of an 1,544 kg car that increases its speed from

Question

A. Find the change in momentum of an 1,544 kg car that increases its speed from 5.3 m/s to 18.2 m/s while traveling in the same direction.

B.An 1,758 kg car increases its speed from 3.4 m/s to 13.5 m/s in a time of 33.6 s while traveling in the same direction. What minimum force, applied in the direction of motion, is needed to do this? Give your answer in Newtons

C. 345 g ball has a kinetic energy 28.1 J. What is the magnitude of its momentum? Give your answers in kg m/s.

D.Two masses are placed at different points along a meter stick of negligible mass: 0.250 kg at 0.200 m and 0.500 kg at 0.500 m. Where's the center of mass of the system?

E.Treating Sun and Earth as symmetric spheres, find the center of mass of the Earth-Sun system. Let the Sun be at x=0.

Explanation / Answer

A) m = 1544 kg

v1 = 5.3 m/s

v2 = 18.2 m/s

change in momentum = m(v2 - v1) = 1544*(18.2 - 5.3) = 19917.6 kg.m/s

B) m = 1758 kg

v1 = 3.4 m/s

v2 = 13.5 m/s

t = 33.6 s

change in momentum = m(v2 - v1) = 1758*(13.5 - 3.4) = 17755.8 kg.m/s

Force = F = 17755.8/33.6 = 528.4 N

C) m = 0.345 kg

KE = 28.1 J

Momentum = p = sqrt(2m*KE) = sqrt(2*0.345*28.1) = 4.4 kg.m/s

D) Two masses are placed at different points along a meter stick of negligible mass: 0.250 kg at 0.200 m and 0.500 kg at 0.500 m. Where's the center of mass of the system?
Let the 0.5 kg be at x = 0.
C.o.M. = 0.25*(0.2+0.5)/(0.25+0.5) = 0.233 m

E) Treating Sun and Earth as symmetric spheres, find the center of mass of the Earth-Sun system. Let the Sun be at x=0.
C.o.M. = (5.98*10^24*1.5*10^8)/(5.98*10^24+2*10^3... = 448.50 km

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