(b) upwara at an angle of 20 with the hortaia 6.3 A tool locker having a mass of
ID: 1781621 • Letter: #
Question
(b) upwara at an angle of 20 with the hortaia 6.3 A tool locker having a mass of 140 kg rests on a Assuming a coefficient of static friction of 0. 0.38, determine the horizontal force that would cause sliding motion to i 6.4 A body weighing 100 lb rests on an inclined plane, as he coefficient of static friction between the body and the plane is 0.40. Compute the force P that will cause impending motion (a) up the inclined plane. (b) down the inclined plane. W=100 lb PROBLEM 6.4 6.5 For Problem 6.4, compute the friction force F when the force 6.6 Block A in the figure shown has a mass of 10 kg and block B P acting up the plane is equal to (a) 40 lb (b) 60 lb (c) 70 lb has a mass of 20 kg. The coefficients of static friction are 0.5 6 between the two blocks and 0.15 between the lower block and the supporting surface. Calculate the force P that will cause motion to impend. PROBLEM 6.6 6.7 Compute the horizontal force P required to cause motion to impend up the plane for the 100 lb block shown. The coeffi- cient of static friction between the block and the plane is 0.25. W = 100 lb 30°Explanation / Answer
Solving 1st question of the page ( as per chegg guidelines)
6.3
Force required=friction force
Friction force=u*N
N=mg=140*9.8
Force required=0.38*140*9.8=521.36 N
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