(5%) Problem 19: In this problem we will observe how the momentum of an electron
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(5%) Problem 19: In this problem we will observe how the momentum of an electron changes as its velocity approaches the speed of light. The mass of an electron is 9.109 × 10-51 kg 14% Part (a) First, what is the momentum of an electron which is moving at the speed of a car on a highway, say 32 m/s, in kilogram meters per second? 14% Part (b) What is the momentum of an electron moving at 15 % of the speed of light, in kilogram meters per second? Grade Summary Deductions10 Potential P2-4.7* 10-23 90% Submissions Attempts remaining: 5 5%per attempt) tan 78 9 HOME CoS asin atan)acotan)sinh) sin cotan acos0 detailed view 5% cosh0 tanh0 cotanh0 0 END 2 5% °Degrees Radians O BACKSPACEDEL CLEAR Submit Hint I give up! Hints: 1 % deduction per hint. Hints remaining: 1 Feedback: 1% deduction per feedback 14% Part (c) What is the momentum of an electron moving at 89 % of the speed of light, in kilogram meters per second? 14% Part (d) What is the non-relativistic momentum of an electron moving at this speed (89 % of the speed of light), in kilogram meters per second? 14% Part(e) when the electron is moving at 89 % of the speed of light, how many times greater is the relativistic momentum than the non-relativistic momentum? 14% Part (f) Which of the following facts are true about the ratio of relativistic to non-relativistic momentum of an electron? 14% Part (g) What is the ratio of the relativistic momentum to the classical momentum of a rocketship moving at 99.3 % of the speed of light, in kg·m/s?Explanation / Answer
momentum=mass time velocity 15c
=0.15*3*10^8
=4.5*10^7
now,we got mass of an electron=9.109*^-31,so
the momentum is =9.109*10^-31*4.5*10^7
=4.09*10^-23.
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