A 1.50 kg snowball is thrown from the roof of a 12.5 m tall building. The initia
ID: 1782475 • Letter: A
Question
A 1.50 kg snowball is thrown from the roof of a 12.5 m tall building. The initial speed of the snowball is 14.0 m / s, directed 41º above the horizontal. Using energy techniques, find the speed of the snowball when it hits the ground. What is the speed b) if the throw angle is changed to 41 ° below the horizontal and c) if the mass is changed to 2.5 kg?A 1.50 kg snowball is thrown from the roof of a 12.5 m tall building. The initial speed of the snowball is 14.0 m / s, directed 41º above the horizontal. Using energy techniques, find the speed of the snowball when it hits the ground. What is the speed b) if the throw angle is changed to 41 ° below the horizontal and c) if the mass is changed to 2.5 kg?
Explanation / Answer
max height reached = ( 14 sin 41^2)/ 19.6= 4.304 m
total height reached= 12. 5 + 4.304 = 16.804 m
mgh = 1/2 mv^2
(9.8x 16.804) = 0.5 v^2
v ( at ground) =18.148 m/s
b) initial vertical velocity = 14 sin 41= 9.185 m/s
mgh + 1/2mu^2 = 1/2 mv^2
9.8 ( 12.5) + 1/2 ( 9.185^2) = 1/2 v^2
v = 18.148 m/s
mass has no impact on velocity
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