Consider a 0.60 kg block which is normally able to slide on a surface without fr

Question

Consider a 0.60 kg block which is normally able to slide on a surface without friction. It is held next to a spring (k 4000 N/m), which is compressed by x = 0.10 m. The block is then horizontally launched by the spring, and then the block moves over a bumpy region (d-1.4m) that exerts a constant friction force Friction on the block. Finally, when the b slides on the h= 2.5 m plateau, it has a velocity of0.87 m/s. How muc energy is lost due to force of friction on the block in the bumpy region? ock h1= 2.51 m h2=2.5 m spring block bumpy area (with friction) d= 1.4

Explanation / Answer

Initial energy imparted by the spring tp the mass, Ei= 0.5 k x*x = 0.5 * 4000* 0.1*.0.1= 20 J

Final energy at plateu (h= 2.5), Ef= mgh + 0.5 mv*v = 0.6 ( 9.8* 2.5+ 0..5 * 0.87*0.87)= 14.927 J

Now loss of energy iis equal to the frictional loss across bumpy surface
Energy lost due to friction= Ei-Ef= 20-14.937 = 5.073 J

Please comment in case any doubt or rate the answer..goodluck

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.