in water. What is the magnitude of the buoyant force acting on the block? 30 N T
ID: 1782792 • Letter: I
Question
in water. What is the magnitude of the buoyant force acting on the block? 30 N Then, eur work in the spaces provided[ 50 % ]. k of woodigralethe Letter that corresponds to the correct answerl 50%) s floating E. ON A. 2.9 N B. 9.8 N C. 29.8 N 2. A manufacturer orders 100 kg ofsome metal ingots. What volume does the metal occupy Take the mass density of the metal to be 89.3 kg m-3 A. 9 m B. 8.9 m 1.12 m? E. 10.7 m2. C) & 93 from a temperature of 24 oC ? The specific heat capacity for aluminum is 890 J / kg.. 3. How much heat must be transferred to each kilogram of aluminum to bring it to its melting point of A. 566 J B. 566 J C. 5.66 x1PJ D. 5.66 x 104 J E. 5.66 ×105J 636) (gro Ans 5.6b 4. Ethyl alcohol boils at 78 °C. The Fahrenheit equivalent of this temperature is A. 351 ( B.) 172°F C. 140 eF D. 78°F E, 32 172.4 5. A 2-kg piston rests on a sample of a gas in a cylinder whose cross-sectional area is 1.5 m2. The pressure the piston exerts on the gas is A. 13 Pa 1.3 Pa C. 130 Pa D. 30 Pa E. 0.13 Pa .9.8 mC471.3066 2x 9.8 .306 Ans 1.3
Explanation / Answer
1)
In equilibrium
net force = 0
along vertical
Fnet , y = 0
Fb - mg = 0
Fb = m*g = 3*10 = 30 N
ANSWER --- (b)
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2)
density = mass/volume
volume = mass/density = 100/89.3 = 1.12 m^3
ANSWER ----( c )
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3)
heat transferred to each kilogram = c*dt = 890*(660-24) = 5.66*10^5 J
ANSWER ---- ( E )
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4)
(F - 32) = (9/5)*c
F = 32 + (9/5)*C
F = 32 + ((9/5)*78)
F = 172.4 = 172 F
ANSWER ----- ( B )
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5)
pressure = force /area = m*g*a
P = 2*10/1.5
P = 13 Pa
ANSWER --- (A)
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