in water how oxygen solubility S varies as a function of the water temperature T

Question

in water how oxygen solubility S varies as a function of the water temperature T on th of the water. (So the oxygen (mg/L) 12 08 16 24 32 40 TOc (o) What is the meaning of the derivative s Tn O s is the current level of oxygen solubility for a given temperature. O s is the rate at which temperature changes with respect to the temperature. s m) is the rate at which oxygen solubility changes with respect to the water temperature. O s (T7 is the rate at which oxygen solubility changes with respect to the oxygen solubility. O s (n is the rate at which temperature changes with respect to the axygen solubility (b) Estimate the value of s (24), (Round your answer to three decimal places.) SY24).3.5 /X (mg/L)/°C

Explanation / Answer

from above derivative of S at 24 will be approxiamted by S'(24) =(S(32)-(S(16))/(32-16) =(7-10)/16=~3/16 = -0.188

please revert, ( for longer range from 0 to 40 it can be 9/40=0.225)

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