A circus acrobat climbs onto her brother\'s shoulders while he, in turn, is stan

Question

A circus acrobat climbs onto her brother's shoulders while he, in turn, is standing on his father's shoulders. They practice the feat while her father is standing on the ground, although the whole things is to be done on the back of a galloping hourse in an acutal performance.

Given: The female acrobat has a mass of 50.kg and must climb a height of 3.0m while the hourse gallps a distance of 7.0m around the ring.

a) How much does the female acrobat weight? answer: 490N

b) How much work must she do in practice while her father is standing stationary on the ground? answer: 1470 J

c) How much additional work must she do in an actual performance while the horse is carrying her (and everyone else) sidewards? answer: 0J (Please help show me how to get here)

Explanation / Answer

She doesn't have to move sideways herself at all. The only displacement she has in vertical that is while climbing up.
Therefore work done = force. displacement = 0 J

Work done is 0 J because there is no displacement at all in the sideways motion in this case.

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