A circular saw blade 0.250m in diameter starts from rest. In5.50s, it reaches an

Question

A circular saw blade 0.250m in diameter starts from rest. In5.50s, it reaches an angular velocity of 130rad/s with constantangular acceleration. Find the angular acceleration and the anglethrough which the blade has turned in this time. A circular saw blade 0.250m in diameter starts from rest. In5.50s, it reaches an angular velocity of 130rad/s with constantangular acceleration. Find the angular acceleration and the anglethrough which the blade has turned in this time. Find the angular acceleration and the anglethrough which the blade has turned in this time.

Explanation / Answer

Given :     Radius ( r ) = 0.250m    Time ( t ) = 5.5 s    Angular velocity ( ) = 130 rad/s      Angular accleration ( ) = / t                                           = 130 rad/s / 5.5 s                                           = 23.63 rad/s2 Angle ( ) = * t                   = ( 130 rad/s ) * ( 5.5s )                   = ------ Solve it I hope it helps you Angle ( ) = * t                   = ( 130 rad/s ) * ( 5.5s )                   = ------ Solve it I hope it helps you

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