A circular loop of wire with a radius of R = 9 cm carries a current of 5.1 A and

Question

A circular loop of wire with a radius of R = 9 cm carries a current of 5.1 A and sits in a uniform external magnetic field with a strength of 6 T. The external magnetic field is pointed up from the plane of the loop at an angle of ? = 38 degrees as shown in the figure.

1) What is the direction of the magnetic field at the center of the loop made by the current I?
a. out of the page
b. down
c. up
d. into the page

2) In what direction will the loop rotate due to the torque from the external magnetic field?
a. counter- clockwise
b. clockwise

3) In the equation we use to find the torque on a loop sitting in an external magnetic field, which angle is used in "sin?"?
a. the angle between a line perpendiculater to the plane of the loop and the magnetic field made by the loop
b. the angle between a line in the plane of the loop and the magnetic field the loop sits in
c. the angle between a line perpendiculatr to the plane of the loop and the magnetic field the loop sits in
d. the angle between a line in the plane of the loop and the magnetic field made by the loop

4) What is the magnitude of the magnetic torque exerted on the loop in the figure?
a. 0.479 Wb
b. 0.614 Wb
c. 0.153 Wb
d. 0.195 Wb
e. 0.779 Wb

Explanation / Answer

Part A)

By the right hand rule, the current direction is DOWN

Part B)

By the right hand rule, the torque will cause a COUNTER-CLOCKWISE Spin

Part C)

The angle between a line perpendicular to the plane of the loop and the magnetic field the loop sits in.

Part D)

Torque = BIAsin(angle)

Torque = 6(5.1)(pi)(.09)2(sin 52)

Torque = .614

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