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1. + 2 points Tipler65-P.077 My Notes Ask Your Teacher A 0.65 kg stone attached

ID: 1783869 • Letter: 1

Question

1. + 2 points Tipler65-P.077 My Notes Ask Your Teacher A 0.65 kg stone attached to a string is whirled in a horizontal circle of radius 49 cm as in the figure below. The string makes an angle of 45o with the vertical. (a) Find the speed of the stone m/s (b) Find the tension in the string. 2 points Tipler65-P.074. My Notes Ask Your Teacher A 0.050-kg ball at the end of a string rotates at constant speed in a vertical circle with a radius of 0.23 m. What is the maximum speed of the ball so that the tension is not to exceed 12 N? m/s

Explanation / Answer

a) T sin theta = m v2 / r

T cos theta = m g

dividing above equations

tan theta = v2 / r g

speed v = sqrt [r g * tan theta] = sqrt [0.49 * 9.8 * tan 45]

v = 2.19 m/s

b) T = m g / cos theta = (0.65 * 9.8) / (cos 45)

= 9.00 N