Question 2 (of 3) alue: .00 points 1 out of 5 attempts Two identical gliders on

Question

Question 2 (of 3) alue: .00 points 1 out of 5 attempts Two identical gliders on an air track are held together by a piece of string, compressing a spring between the gliders. While they are moving to the right at a common speed of 0.34 m/s, someone holds a match under the string and burns it, letting the spring force the gliders apart. One glider is then observed to be moving to the right at 1.89 m/s. Part 1 out of 2 (a) What velocity does the other glider have? m/s to the (select) (select) left a right next

Explanation / Answer

Before burning the string :

Consider the two balls along with spring and string as single system

Suppose mass of each ball is m kg (since both the balls are identical)

Initial velocity of this single system (taking right as positive x- direction)

Vi = 0.34 m/s

After burning the string:

both balls are getting apart,

final velocity of ball 1, Vf1 = 1.89 m/s (moving towards right ,so in positive x- direction )

let final velocity of ball 2 is Vf2

Apply the law of conservation of momentum:

Initial momentum of the system (before burning the string) = Final momentum of the system(after burning)

(m1+m2) * Vi = m1 * Vf1 + m2 * Vf2

(m + m)* 0.34 = m * 1.89 + m * Vf2

m will cancel out from both side

2 * 0.34 = 1.89 + Vf2

Vf2 = 0.68 - 1.89 = (- 1.21 m/s)

so, other glider have velocity of 1.21 m/s moving towards left & it is true since the initially spring is compressed, so it will force both balls in opposite direction when string is being burn.

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