A single-turn rectangular wire loop measures 6.00 cm wide by 10.0 cm long. The l

Question

A single-turn rectangular wire loop measures 6.00 cm wide by 10.0 cm long. The loop carries a current of 2.00 A. The loop is in a uniform magnetic field with B = 3.00 x 10-3T. Taking torques about an axis, parallel to either side of the rectangular loop, that maximizes the torque, what is the magnitude of the torque exerted by the field on the loop if the direction of the magnetic field is described as the following? (a) parallel to the short sides of the loop 0.024 (o) paralilel to the long sides of the loop 0.024 (c) perpendicular to the plane of the loop N·m

Explanation / Answer

Torque is given by

t = (W/2)*L*I*B*sin(theta)

Here for maximum torque, sin(theta) should be 1.

So in both the cases, the torque is 0.018*10^-3 N.m

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