Hi, I am looking at the way to work out the solution to this question https://ww

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Hi, I am looking at the way to work out the solution to this question https://www.chegg.com/homework-help/Delmar-s-Standard-Textbook-of-Electricity-6th-edition-chapter-23-problem-3RQ-solution-9781285852706 Going through the question, I thought that the Voltage stays the same in a parallel circuit. Why is it that the explaination of the soltution has it all doubled to 240v?

Edit: It is given that R=40 C=132.6 and Et=120v The reistive current in the parallel circuit is the amount of current flow through the resistor (Ir) can be calculated using a formula Ir= E/R. The question then goes on to use 240v/40 to = 6 Amps. What does it change it to 240 Volts instead of keeping it to 120 volts. Voltage stays the same in a parallel circuiit. So the formula should read 120v/40=3Amps. If ou click here---> https://www.chegg.com/homework-help/Delmar-s-Standard-Textbook-of-Electricity-6th-edition-chapter-23-problem-5RQ-solution-9781285852706 you can see.

Explanation / Answer

As given that capacitor and resistor are connected in parallel to a 120 V line.

so voltage will be 120 V on each.

Current flow through resistor,

lR = E / R

lR = 120 / 40

lR = 3 A

Reactive capacitance of capacitor,

xC = 1 / 2*pi*f*C

xC = 1 / 2*3.14*60*132.6*10^(-6)

xC = 20 Hz

Current through capacitor,

lC = E / xC

lC = 120 / 20

lC = 6 A

Total current flow through the circuit,

l = sqrt (lR^2 + lC^2)

l = sqrt (3^2 + 6^2)

l = 6.7 A

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