This is one question broken down into many parts. Most everyone in our class mis

Question

This is one question broken down into many parts. Most everyone in our class missed this question, and I would like to know the correct answer.

Many months from now on a warm summer day you and your friends decide to use a water balloon launcher to launch water balloons from a rooftop. The balloon is launched horizontally to the right with a speed of 15 m/s from a 46 m rooftop. What are the x- and y- components of the initial velocity? Use "Up" for the positive y-direction and "Right" for the positive x-direction Vix = 0 m/s, Vi,y = 15m/s Vi,,-4.65 m/s, vi,y-1 4.26 m/s Vi,x = 15 m/s, v,y = 14.26 m/s .vix = 15 m/s, yy-15m/s Vi,x = 15m/s, Vi,y = 0 m/s Submit Answer Tries 0/1 What are the x- and y- components of the acceleration while the water balloon is in flight? Use "Up" for the positive y- direction and "Right" for the positive x-direction s-, av- O ax =-gm/s2, ay = 0 m/s2 Submit AnswerTries 0/1 For the Y-DIRECTION, what is the correct kinematic equation? Oo46+15t +(1/2)g t2 0 0 = 46-(1 /2)g t2 Oo46+15t - (1/2)g t2 O46 (1/2)g t2

Explanation / Answer

Q.1 Vix = 15 m/s , Viy = 0 m/s *(the ballon is luanched horizontally, therefore it will have no initial vertical velocity)

Q.2 : ax = 0m/s ^2 , ay = -g m/s^2 ( accleration will occur only due to gravity n the -ve y direction)

Q. 3:

- 46 =- 1/2 gt^2

46 - 1/2 gt^ 2= 0

Q: 4 xf = vt = 15 ( t)

Q/5

t = sqroot ( 2h/g) = 3.06 seconds

Q. 6

X = 15 (3.06) = 46 m

Q: 7

Vy = 9.8 (3.06) = 30 m/s

Vx = 15

V = sqroot ( Vx^2+ Vy^2) = 33.6 m/s apprx

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