The two forces F 1 and F 2 shown in (Figure 1) act on a 29.0-kg object on a fric

ID: 1785458 • Letter: T

Question

The two forces F 1 and F 2 shown in (Figure 1) act on a 29.0-kg object on a frictionless tabletop. Suppose that F1 = 10.6 N , and F2 = 17.0 N .

i Determine the magnitude of the net force on the object for the diagram (a) in the figure.

Express your answer to three significant figures and include the appropriate units.

ii. Determine the angle between the positive x axis and the net force F Ra on the object for the diagram (a), measured countercockwise.

Express your answer using three significant figures.

iii. Determine the magnitude of the acceleration of the object for the diagram (a).

Express your answer to three significant figures and include the appropriate units.

iv. Determine the magnitude of the net force on the object for the diagram (b) in the figure.

Express your answer to three significant figures and include the appropriate units.

v. Determine the angle between the positive x axis and the net force F Rb on the object for the diagram (b), measured countercockwise.

Express your answer using three significant figures.

vi. Determine the magnitude of the acceleration of the object for the diagram (b).

Express your answer to three significant figures and include the appropriate units.

120 90°

I) magntiude = sqrt(F1^2 + F2^2)

= sqrt(10.6^2 + 17^2)

= 20.03 N

angle = tan^-1 ( 17/10.6) = 58.05

180 + 58.05 = 238.05 o in counter clockwise direction

magntiude of acceleration = F/m = 20.03/29 = 0.69 m/s2

for b)

net force in x-direction = F1 cos 30 = 10.6 cos 30 = 9.18 N

net force in y-direction = F2 - F1 sin 30 = 17 - 10.6*sin 30 = 11.7 N

net force = sqrt(9.18^2 + 11.7^2) = 14.87 N

angle = tan^-1 ( 11.7 / 9.18) = 51.88o in the counterclockwise direction

Acceleration = F/m = 14.87 / 29 = 0.51 m/s2

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