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kmarks Window Help College Physics :Chapter 6-10th Ed 0 011 points l Previous An

ID: 1785846 • Letter: K

Question

kmarks Window Help College Physics :Chapter 6-10th Ed 0 011 points l Previous Answers CJ10 5P003. One kind of slingshot consists of a pocket that holds a pebble and is whirled on a circle of radius r. The pebble is released from the circde at the angle 8 so that it will ht the target. The angle in the drawing is 39.6". The distance to the target f om the d See the dra been and the target lies in the plane of the circle. The distance d is eleven times the radius r. Ignore the effect of gravity in center of the circdle is d. (See the drawing beliow, which is not to scale.) The circular path a purale' to the pround, of gravity in pulling the stone downward after it is released and find the angle Target -. ), Pebble Additional Materials section 52

Explanation / Answer


Given that

Phi = 39.6 degree

distance d = 11r

here r = radius of the path

From the diagram

cos(alpha) = r / d

= r / 11*r

= 1 /11

this implies

alpha = cos^-1(1/11)

= 84.784 degree

Thus the angle

thita = 180 - (alpha + phai)

= 180 - (84.784 + 39.6)

= 55.61 degree