I dont know what i am doing wrong in Part C, Please advise and show work Wgr- -8

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I dont know what i am doing wrong in Part C, Please advise and show work

Wgr- -8.9x104 J Problem 9.43 - Enhanced with Video Solution Submit My Answers Give Up A 700 kg elevator accelerates upward at 1.8 m/s2 for 13 m, starting from rest Correct You may need to review ( page 206) Part B How much work does the tension in the elevator cable do on the elevator? Express your answer with the appropriate unit:s Wr= 1.1x105 J Submit My Answers Give Up Correct Part C What is the elevator's kinetic energy after traveling 13 m? Express your answer with the appropriate unit:s K= 2.1 . 1041J Submit My AnswersGive Up Incorrect, Iry Again, 2 attempts remaining

Explanation / Answer

C)Given,

m = 700 ; a = 1.8 m/s^2 ; S = 13 m

We know from eqn of motion

v^2 = u^2 + 2 a S

v = sqrt (2 a S)

v = sqrt (2 x 1.8 x 13) = 6.84 m/s

KE = 1/2 m v^2

KE = 0.5 x 700 x 6.84^2 = 1.64 x 10^4 J

Hence, KE = 1.64 x 10^4 J

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