I dont know what I am doing wrong for part A, direction. Question: Two forces ar

Question

I dont know what I am doing wrong for part A, direction.

Question: Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 437 N and F2 = 370 N. (Assume up and to the right as positive directions.)

Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 437 N and F2 = 370 N. (Assume up and to the right as positive directions.) What is the resultant of these two forces? magnitude 758.678 N direction degree to the right of the forward direction If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. 252 m/s2

Explanation / Answer

a is the angle with F2.

sin(a) = F1 * sin(10 + 30) / Fr

= 437 * sin(40) / 758.678

= 0.3702

a = asin(0.3702)

a = 21.731 degrees.

To the right of forward direction

theta = 30 - 21.731

= 8.269 degrees

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