4:27 PM webassign.net .il Verizon LTE -3 painta 3HIPSFTA 7.PCEO A single conserv

Question

4:27 PM webassign.net .il Verizon LTE -3 painta 3HIPSFTA 7.PCEO A single conservative force acting on a particle within a system varies as F=,-Ax +Be" N, where A and B are constants, i is in newtons, and x is in meters My Nobwa Ask Your (a) Calculate the potential energy function U(x) associated with this force, taking u-o at x=0. (Use any variable or symbol stated above as necessary.) ix)- (b) Find the change in potential energy as the particle moves from x= 1.70 m to 4.00 m. (Use any variable or symbol stated above as necessary.) (c) Find the change in kinetic energy as the particle moves from x=1.70 m to x - 4.00 m. (Use any variable or symbol stated above as necessary.) AK- Need Help? RadIt 6. -2 points 3erPSET9 8.PCO7.MI. My Note + Ask Your Two objects are connected by a light string passing over a light, frictionless pulley as shown in the figure below. The object of mass m1-6.60 kg is released from rest at a height h = 3.20 m above the table (a) Using the isolated system model, determine the speed of the object of mass m2-3.00 kg just as the 6.60-kg object hits the table m/s (b) Find the maximum height above the table to which the 3.00-kg object rises Need Help? Read itMaster -4 paint* 3HtP8FT9 11 Paso A disk with moment of inertia I1 rotates about a frictionless, vertical axle with angular speed o. A second disk, this one having moment of inertia I2 My Nobwa Ask Your

Explanation / Answer

6.

a)

using conservation of energy

m1 gh = m2 gh + (0.5) (m1 + m2) v2

(6.6) (9.8 x 3.20) = (3) (9.8 x 3.20) + (0.5) (6.6 + 3) v2

v = 4.85 m/s

b)

consider the motion of 3 kg block .

Yo = h = 3.20 m

Y = maximum height

vo = initial velocity = 4.85 m/s

v = final velocity the maximum height = 0 m/s

a = acceleration = - 9.8

using the equation

v2 = vo2 + 2 a (Y - Yo)

02 = 4.852 + 2 (-9.8) (Y - 3.20)

Y = 4.4 m

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