Thanks for any help here: (1) an aluminum casting that weighs 10 pounds sits on

Question

Thanks for any help here:

(1) an aluminum casting that weighs 10 pounds sits on a steel surface. How much force will be necessary to get it to start sliding? The static coefficient of friction (mu) for aluminum on steel is 0.61.

(2) A robot arm must be able to extend 50 cm in 2 s. while carrying a load of 5 kg. How much force is required in Newtons?

(3) A small gasoline engine can put out 24,000 N-m/min of mechanical power. The engine is used to drive an electrical generator that is 70 percent efficient. 1 N-m = 2.78 X 10-4
W-h. Find the output of the generator in Watts.

Explanation / Answer

1)Given,

W = 10 lb = 44.48 N ; u = 0.61

The casting will begin to slide once the frictional force will overcome, So the minimum amount of force will be:

F = u (mg) = 0.61 x 10 = 6.1 lb

Hence, F = 6.1 lb

[Pls put one question at a time. Check and rate and let me know for any query. Thanks]

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