(1394) Problem 4: A rod of m = 0.45 kg and L = 0.45 m is on a ramp of two parall
ID: 1787548 • Letter: #
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(1394) Problem 4: A rod of m = 0.45 kg and L = 0.45 m is on a ramp of two parallel rails with angle = 24° with respect to the horizontal. The current on the rod is 1= 4.1 A, pointing into the screen as shown. A uniform magnetic field B = 0.55 T which points upward is applied in the region. Ignore the friction on the rails. ---- V 10% Part (a) Express the magnitude of the magnetic force in terms of L, I and B. V 10% Part (b) Calculate the numerical value of the magnitude of the magnetic force in N. A 10% Part (C) Which direction is the magnetic force? * 10% Part (d) Express the component of the magnetic force parallel to the ramp in terms of F3 and . * 10% Part (e) Express the component of the weight parallel to the ramp in terms of m, g and e. Take up the ramp to be positive. * 10% Part (1) Calculate the numerical value of the net force Fn parallel to the ramp, assuming the positive direction is up the ramp in N. Grade Summary Fn= - 0,68|| Deductions 5% Potential 95% sin() cos() tan() a ( 7 8 9 HOME Submissions cotan() asin() acos() 1*|| 4 5 6 Attempts remaining. 14 (5% per attempt) atan) acotan() sinh). /* 1 2 3 detailed view cosh() tanh() cotanh) END 5% O Degrees O Radians VO BACKSPACE DEL CLEAR Hint Submit Hints: 2% deduction per hint. Hints remaining: 1 Feedback I give up! Feedback: 2% deduction per feedback. A 10% Part (g) Express the acceleration along the ramp in terms of the F, and m. A 10% Part (h) Calculate the numerical value of a in m/s2. E A 10% Part (i) If a is positive, which direction does the rod go? E A 10% Part () If a is negative, which direction does the rod go?Explanation / Answer
d)
F_B x= F_B * cos theta
(e)
W= - mg sin theta
(f)
F_n = BIL - mg sin theta
= ( 0.55) ( 4.1) ( 0.45) - 0.45 ( 9.8) sin24
=-0.77 N
(g)
a= F_n/m
(h)
a= -0.77 N/0.45 = -1.73 m/s^2
(i)
North-Eastern (upward in the ramp)
(j)
south-western (downward in the ramp)
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