#6 (a-b) nline HW 09 Begin Date: 11/10/2017 5:00:00 PM Due Date: 1120/2017 5:00:
ID: 1787669 • Letter: #
Question
#6 (a-b)
nline HW 09 Begin Date: 11/10/2017 5:00:00 PM Due Date: 1120/2017 5:00:00 PM End Date: II/24/2017 5:00:00 PM CG (1006) Problem 6: A-9-kg man stands on his toes by exerting an upward force through the Achilles tendon, as shown in the figure. 4.0 Otheexpertta.com 50% Part (a) what is the force in newtons in the Achilles tendon if he stands on one foot? 5000 Part(b) Calculate the force in newtons at the pivot of the simplified lever system shown that force is representative of forces in the ankle joint. Grade Summary 0% 100% potential sin() | cos() |. tan() | | (1-)17| 8| 9 HOh cotan asin) atan acotan sinh Submissions Attempts remaining: 7 (1% per attempt) detailed viewExplanation / Answer
part(a)
normal force N = m*g
In equilibrium net torque about pivot = 0
N*0.12 - FA*0.04 = 0
m*g*0.12 - FA*0.04 = 0
79*9.8*0.12 - FA*0.04 = 0
Force in Achilles muscle = 2322.6 N
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part(b)
In equilbrium net force = 0
Fy,net = 0
-Fp + FA + N = 0
-Fp + 2322.6 - (79*9.8) = 0
Fp = 1548.4 N <<<<--------ANSWER
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