#6 . Advanc. × the mass is 3.40 kg, T-23 N, and = 33 degrees. The surface does h

Question

#6 . Advanc. × the mass is 3.40 kg, T-23 N, and = 33 degrees. The surface does have friction, with As ,45 and A:-39. If x ls hortertal and y is vertical,- b) is Ty? N up. N up d) What is the friction? N right. What is the net force on the block in the x-direction? N right. f) What is the net force of the block in the y-direction? No Response)N up. ) What is the acceleration of the block? m/sec+2 right h) What will be the position of the block after 6 seconds if it starts from a position 3 m from the left of the origin at a speed of 5 m/sec right? m night

Explanation / Answer

(a) Tx = T cos33 = 19.3 N  

(b) Ty = T sin33 = 12.5 N

(c) in vertical,

Fnet = Ty + N - m g = 0

N = (3.40 x 9.8) - 12.5

N = 20.8 N

(d) fs_max = us N = 0.45 x 20.8 = 9.36 N that is less than Tx.

so block will move and kinetic friction will act.

f =uk N = 8.11 N ....Ans

(e) Fnet = Tx - f = 11.2 N  

(f) Fnet in y = 0 (at equilibrium)

(g) a = Fnet / m = 11.1 / 3.40 = 3.29 m/s^2

(h) xf - xi = v0 t + a t^2 /2

x -(-3) = (5 x 6) + (3.29 x 6^2 / 2)

x = 86.2 m

i) v = v0 + a t

v = 5 + (3.29 x 6)

v = 24.7 m/s

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